Difference between revisions of "DOM Changing elements"
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<pre class='usr'> | <pre class='usr'> | ||
</pre> | |||
<pre class='ans'> | |||
document.querySelectorAll('img').forEach(i=>{ | |||
i.style.width = '50px'; | |||
i.style.border = 'solid'; | |||
}); | |||
</pre> | |||
</div> | |||
==Give the flags borders, make the heading bigger== | |||
<div class='qu'> | |||
<div class=imper>Make the width of all img 50px, make the border solid</div> | |||
<pre class='usr'> | |||
document.querySelectorAll('img').forEach(i=>{ | |||
i.style.width = '50px'; | |||
i.style.border = 'solid'; | |||
}); | |||
document.querySelectorAll('#countries>div>div').forEach(i=>{ | |||
i.style.fontSize = '200%'; | |||
}); | |||
</pre> | </pre> | ||
<pre class='ans'> | <pre class='ans'> |
Revision as of 16:29, 14 August 2022
<div id='countries'> <div id='fr'> <div>France</div> <img src='/flags/fr.gif'/> </div> <div id='fi'> <div>Finland</div> <img src='/flags/fi.gif'/> </div> </div>
In these examples the web page contains the following content.
<div id='countries'> <div id='fr'> <div>France</div> <img src='/flags/fr.gif'/> </div> <div id='fi'> <div>Finland</div> <img src='/flags/fi.gif'/> </div> </div>
Change an element based on id
If the element you want to change has an id you can use getElementById
- The html above has a div with id "countries"
Change the countries div to have silver background color.
let e = document.getElementById('countries'); e.style.backgroundColor = 'pink';
let e = document.getElementById('countries'); e.style.backgroundColor = 'silver';
Find an element and change it
You can use document.querySelector to find elements. The pattern given is very like the patterns you use in CSS.
- 'img' will match a <img/> element
- '#fr' will match an element with id fr
Make the width of the first img 50px
document.querySelector('img').style.width = '75px';
document.querySelector('img').style.width = '50px';
Find many elements, change them all
You can use document.querySelectorAll to lots of elements.
- You can visit every element in the list with forEach
- The default program changes every img element
Make the width of all img 50px
document.querySelectorAll('img').forEach(i =>{ i.style.width = '75px'; })
document.querySelectorAll('img').forEach(i=>{ i.style.width = '50px'; });
Give the flags borders
Make the width of all img 50px, make the border solid
document.querySelectorAll('img').forEach(i=>{ i.style.width = '50px'; i.style.border = 'solid'; });
Give the flags borders, make the heading bigger
Make the width of all img 50px, make the border solid
document.querySelectorAll('img').forEach(i=>{ i.style.width = '50px'; i.style.border = 'solid'; }); document.querySelectorAll('#countries>div>div').forEach(i=>{ i.style.fontSize = '200%'; });
document.querySelectorAll('img').forEach(i=>{ i.style.width = '50px'; i.style.border = 'solid'; });
Remove France
The element with id fr must go.
Use .remove() to remove France
document.querySelector('#fr').remove();
Swap the order
You can use append to reinsert an element.
- You must find the list of countries
- You must find the target country
- You must append the target to the list
Use .append() to put France at the end
document.getElementById('countries') .append(document.getElementById('fr'));