DOM Changing elements: Difference between revisions
		
		
		
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You can use document.querySelectorAll to lots of elements.  | You can use document.querySelectorAll to lots of elements.  | ||
*You can visit every element in the list with forEach  | *You can visit every element in the list with forEach  | ||
*The default program changes every img element  | |||
<div class=imper>Make the width of all img 50px</div>  | <div class=imper>Make the width of all img 50px</div>  | ||
<pre class='usr'>  | <pre class='usr'>  | ||
document.  | document.querySelectorAll('img').forEach(i =>{  | ||
  i.style.width = '75px';  | |||
})  | |||
</pre>  | </pre>  | ||
<pre class='ans'>  | <pre class='ans'>  | ||
| Line 68: | Line 71: | ||
</div>  | </div>  | ||
==  | ==Give the flags borders==  | ||
<div class='qu'>  | <div class='qu'>  | ||
<div class=imper>Make the width of all img 50px, make the border solid</div>  | |||
<pre class='usr'>  | |||
</pre>  | |||
<pre class='ans'>  | |||
document.querySelectorAll('img').forEach(i=>{  | |||
  i.style.width = '50px';  | |||
  i.style.border = 'solid';  | |||
});  | |||
</pre>  | |||
</div>  | |||
==Give the flags borders, make the heading bigger==  | |||
<div class='qu'>  | |||
* A pattern such as <code>#countries>div>div</code> will match the node containing the country name  | |||
* You can use <code>i.style.fontSize = '200%'</code> to make the text in element <code>i</code> twice the size.  | |||
<div class=imper>Make the width of all img 50px, make the border solid</div>  | |||
<pre class='usr'>  | |||
document.querySelectorAll('img').forEach(i=>{  | |||
  i.style.width = '50px';  | |||
  i.style.border = 'solid';  | |||
});  | |||
</pre>  | |||
<pre class='ans'>  | |||
document.querySelectorAll('img').forEach(i=>{  | |||
  i.style.width = '50px';  | |||
  i.style.border = 'solid';  | |||
});  | |||
document.querySelectorAll('#countries>div>div').forEach(i=>{  | |||
  i.style.fontSize = '200%';  | |||
});  | |||
</pre>  | |||
</div>  | |||
==Remove France==  | |||
<div class='qu'>  | |||
The element with id '''fr''' must go.  | |||
<div class=imper>Use .remove() to remove France</div>  | <div class=imper>Use .remove() to remove France</div>  | ||
| Line 77: | Line 118: | ||
<pre class='ans'>  | <pre class='ans'>  | ||
document.querySelector('#fr').remove();  | document.querySelector('#fr').remove();  | ||
</pre>  | |||
</div>  | |||
==Swap the order==  | |||
<div class='qu'>  | |||
You can use append to reinsert an element.  | |||
*You must find the list of countries  | |||
*You must find the target country  | |||
*You must append the target to the list  | |||
<div class=imper>Use .append() to put France at the end</div>  | |||
<pre class='usr'>  | |||
</pre>  | |||
<pre class='ans'>  | |||
document.getElementById('countries')  | |||
  .append(document.getElementById('fr'));  | |||
</pre>  | </pre>  | ||
</div>  | </div>  | ||
Latest revision as of 16:32, 14 August 2022
<div id='countries'> <div id='fr'> <div>France</div> <img src='/flags/fr.gif'/> </div> <div id='fi'> <div>Finland</div> <img src='/flags/fi.gif'/> </div> </div>
In these examples the web page contains the following content.
<div id='countries'> <div id='fr'> <div>France</div> <img src='/flags/fr.gif'/> </div> <div id='fi'> <div>Finland</div> <img src='/flags/fi.gif'/> </div> </div>
Change an element based on id
If the element you want to change has an id you can use getElementById
- The html above has a div with id "countries"
 
Change the countries div to have silver background color.
let e = document.getElementById('countries');
e.style.backgroundColor = 'pink';
let e = document.getElementById('countries');
e.style.backgroundColor = 'silver';
Find an element and change it
You can use document.querySelector to find elements. The pattern given is very like the patterns you use in CSS.
- 'img' will match a <img/> element
 - '#fr' will match an element with id fr
 
Make the width of the first img 50px
document.querySelector('img').style.width = '75px';
document.querySelector('img').style.width = '50px';
Find many elements, change them all
You can use document.querySelectorAll to lots of elements.
- You can visit every element in the list with forEach
 - The default program changes every img element
 
Make the width of all img 50px
document.querySelectorAll('img').forEach(i =>{
  i.style.width = '75px';
})
document.querySelectorAll('img').forEach(i=>{
  i.style.width = '50px';
});
Give the flags borders
Make the width of all img 50px, make the border solid
document.querySelectorAll('img').forEach(i=>{
  i.style.width = '50px';
  i.style.border = 'solid';
});
Give the flags borders, make the heading bigger
- A pattern such as 
#countries>div>divwill match the node containing the country name - You can use 
i.style.fontSize = '200%'to make the text in elementitwice the size. 
Make the width of all img 50px, make the border solid
document.querySelectorAll('img').forEach(i=>{
  i.style.width = '50px';
  i.style.border = 'solid';
});
document.querySelectorAll('img').forEach(i=>{
  i.style.width = '50px';
  i.style.border = 'solid';
});
document.querySelectorAll('#countries>div>div').forEach(i=>{
  i.style.fontSize = '200%';
});
Remove France
The element with id fr must go.
Use .remove() to remove France
document.querySelector('#fr').remove();
Swap the order
You can use append to reinsert an element.
- You must find the list of countries
 - You must find the target country
 - You must append the target to the list
 
Use .append() to put France at the end
document.getElementById('countries')
  .append(document.getElementById('fr'));