DOM Changing elements
Revision as of 16:21, 14 August 2022 by Andr3w (talk | contribs) (→Find many elements, change them all)
<div id='countries'> <div id='fr'> <div>France</div> <img src='/flags/fr.gif'/> </div> <div id='fi'> <div>Finland</div> <img src='/flags/fi.gif'/> </div> </div>
In these examples the web page contains the following content.
<div id='countries'> <div id='fr'> <div>France</div> <img src='/flags/fr.gif'/> </div> <div id='fi'> <div>Finland</div> <img src='/flags/fi.gif'/> </div> </div>
Change an element based on id
If the element you want to change has an id you can use getElementById
- The html above has a div with id "countries"
Change the countries div to have silver background color.
let e = document.getElementById('countries'); e.style.backgroundColor = 'pink';
let e = document.getElementById('countries'); e.style.backgroundColor = 'silver';
Find an element and change it
You can use document.querySelector to find elements. The pattern given is very like the patterns you use in CSS.
- 'img' will match a <img/> element
- '#fr' will match an element with id fr
Make the width of the first img 50px
document.querySelector('img').style.width = '75px';
document.querySelector('img').style.width = '50px';
Find many elements, change them all
You can use document.querySelectorAll to lots of elements.
- You can visit every element in the list with forEach
- The default program changes every img element
Make the width of all img 50px
document.querySelectorAll('img').forEach(i =>{ i.style.width = '75px'; })
document.querySelectorAll('img').forEach(i=>{ i.style.width = '50px'; });
Remove France
The element with id fr must go.
Use .remove() to remove France
document.querySelector('#fr').remove();
Swap the order
You can use append to reinsert an element.
- You must find the list of countries
- You must find the target country
- You must append the target to the list
Use .append() to put France at the end
document.getElementById('countries') .append(document.getElementById('fr'));