DOM content from lists
beatles.json
{"members":
[
{"firstName":"Paul","lastName":"McCartney"},
{"firstName":"John","lastName":"Lennon"},
{"firstName":"Ringo","lastName":"Starr"},
{"firstName":"George","lastName":"Harrison"}
],
"albums":
[
{"title":"Please Please Me", "year":1963},
{"title":"With the Beatles","year":1963},
{"title":"A Hard Day's Night","year":1964},
{"title":"Beatles for Sale","year":1964},
{"title":"Help!","year":1965},
{"title":"Rubber Soul","year":1965},
{"title":"Revolver","year":1966},
{"title":"Sgt. Pepper's Lonely Hearts Club Band","year":1967},
{"title":"Magical Mystery Tour","year":1967},
{"title":"White Album","year":1968},
{"title":"Yellow Submarine","year":1969},
{"title":"Abbey Road","year":1969},
{"title":"Let It Be","year":1970}]
}
1) Using a for loop
- When you have data in a list you can use a for loop to generate content
Input
xxxxxxxxxxfetch('/beatles.json') .then((r)=>r.json()) .then((r)=>{ for(let b of r.members){ let div = document.createElement('div'); div.innerHTML = `${b.lastName}, ${b.firstName}`; document.body.append(div); } });Output
fetch('/beatles.json')
.then((r)=>r.json())
.then((r)=>{
for(let b of r.members){
let div = document.createElement('div');
div.innerHTML = `${b.lastName}, ${b.firstName}`;
document.body.append(div);
}
});
fetch('/beatles.json')
.then((r)=>r.json())
.then((r)=>{
for(let beatle of r.members){
let div = document.createElement('div');
div.innerHTML = `${beatle.firstName} ${beatle.lastName}`;
document.body.append(div);
}
});
2) Using forEach
- An alternative is the forEach method
Input
xxxxxxxxxxfetch('/beatles.json') .then((r)=>r.json()) .then((r)=>{ r.members.forEach(b => { let div = document.createElement('div'); div.innerHTML = `${b.lastName}, ${b.firstName}`; document.body.append(div); }) });Output
fetch('/beatles.json')
.then((r)=>r.json())
.then((r)=>{
r.members.forEach(b => {
let div = document.createElement('div');
div.innerHTML = `${b.lastName}, ${b.firstName}`;
document.body.append(div);
})
});
fetch('/beatles.json')
.then((r)=>r.json())
.then((r)=>{
r.members.forEach(b => {
let div = document.createElement('div');
div.innerHTML = `${b.firstName} ${b.lastName}`;
document.body.append(div);
})
});
3) Using map
r.albums is a list, each entry includes a title and year
- We use
mapto createlst - Each element of
lstmust be added to the document body. - If you don't want to add each of the 13 items by hand you'll have to find out how to use spread syntax.
Input
xxxxxxxxxxfetch('/beatles.json') .then((r)=>r.json()) .then((r)=>{ let lst = r.albums.map(a => { let div = document.createElement('div'); div.innerHTML = `${a.title}, ${a.year}`; return div }); document.body.append(lst[0],lst[1],lst[2]); });Output
fetch('/beatles.json')
.then((r)=>r.json())
.then((r)=>{
let lst = r.albums.map(a => {
let div = document.createElement('div');
div.innerHTML = `${a.title}, ${a.year}`;
return div
});
document.body.append(lst[0],lst[1],lst[2]);
});
fetch('/beatles.json')
.then((r)=>r.json())
.then((r)=>{
document.body.append(... r.albums.map(b => {
let div = document.createElement('div');
div.innerHTML = `${b.title}, ${b.year}`;
return div
}));
});
4) Create a drop down list
In HTML you can create a drop down list like this:
<select> <option>One</option> <option>Two</option> <option>Three</option> </select>
Create a drop down list for every Album. Show the year only
Input
xxxxxxxxxxfetch('/beatles.json') .then((r)=>r.json()) .then((r)=>{ let s = document.createElement('ul'); s.append(r.albums.map(a => { let o = document.createElement('li'); o.innerHTML = `${a.title}`; return o })); document.body.append(s); });Output
fetch('/beatles.json')
.then((r)=>r.json())
.then((r)=>{
let s = document.createElement('ul');
s.append(...r.albums.map(a => {
let o = document.createElement('li');
o.innerHTML = `${a.title}`;
return o
}));
document.body.append(s);
});
fetch('/beatles.json')
.then((r)=>r.json())
.then((r)=>{
let s = document.createElement('select');
s.append(...r.albums.map(a => {
let o = document.createElement('option');
o.innerHTML = `${a.year}`;
return o
}));
document.body.append(s);
});
5) Create a drop down list of unique years
You can convert an Array to a Set then back again. That will remove duplicates.
Create a drop down list for every Album. Show each year once only
Input
xxxxxxxxxxfetch('/beatles.json') .then((r)=>r.json()) .then((r)=>{ let ls = Array.from(new Set(r.albums.map(r=>r.year))); let s = document.createElement('ul'); s.append(ls.map(a => { let o = document.createElement('li'); o.innerHTML = a; return o })); document.body.append(s); });Output
fetch('/beatles.json')
.then((r)=>r.json())
.then((r)=>{
let ls = Array.from(new Set(r.albums.map(r=>r.year)));
let s = document.createElement('ul');
s.append(...ls.map(a => {
let o = document.createElement('li');
o.innerHTML = a;
return o
}));
document.body.append(s);
});
fetch('/beatles.json')
.then(r=>r.json())
.then(r=>{
let lst = new Set(r.albums.map(a=>`${a.year}`));
lst = Array.from(lst);
let s = document.createElement('select');
s.append(...lst.map(a => {
let o = document.createElement('option');
o.innerHTML = a;
return o
}));
document.body.append(s);
});